string is composed ofn(20) characters in an orderly sequence recorded as s:“c1C2C3…Cn” S is string name c123n is value is a character n is string length Such as,S=“ TSinghua University
§13-1 概述(Introduction) §13-2 杆件变形能的计算( Calculation of strain energy for various types of loading ) §13-3 互等定理(Reciprocal theorems) §13-4 单位荷载法 • 莫尔定理(Unit-load method & mohr’s theorem) §13-5 卡氏定理(Castigliano’s Theorem) §13-6 计算莫尔积分的图乘法 (The method of moment areas for mohr’s integration)
2-1 设 n 个人围坐在一个圆桌周围,现在从第 s 个人开始报数,数到第 m 个人,让他出局;然后从出 局的下一个人重新开始报数,数到第 m 个人,再让他出局,……,如此反复直到所有的人全部出局为 止。下面要解决的 Josephus 问题是:对于任意给定的 n, s 和 m,求出这 n 个人的出局序列。请以 n = 9, s = 1, m = 5 为例,人工模拟 Josephus 的求解过程以求得问题的解
Chapter 10 Topics Built-In Simple Types s Integral and Floating Point Data Types s Using Combined Assignment Operators s Prefix and Postfix Forms of Increment and Decrement Operators Additional C++ Operator