void swap(int*a, int*b) int x, y, printf(℃\请输入两个整数ⅹ和y:\) scanf(\%od%d\, &x, &y) printf\交换前x和y的值为:\) printf(x=%dy=%d\\n\x, y);

2005年数学二试题分析、详解和评注 一、填空题(本题共6小题,每小题4分,满分24分.把答案填在题中横线上) (1)设y=(1+sinx),则dy =-ndx. 【分析】本题属基本题型,幂指函数的求导(或微分)问题可化为指数函数求导或 取对数后转化为隐函数求导 【详解】方法一:y=(1+sinx)x= xInsin,于是 '=e(+) [In(+sin)+x. cos ] y'=e

1.I intraduce the history of the event, the technical 内容 characteristic of the discus throw and study task to students. 2. students discus the 3. students study swing action and release action initially. 4. students stu dy facing throw action initially