1、罗尔中值定理 罗尔（Rolle）定理 如果函数f (x)在闭区间 [a,b]上连续,在开区间(a,b)内可导,且在区间端 点的函数值相等，即 f (a) = f (b),那末在(a,b) 内至少有一点(a    b),使得函数f (x)在该 点的导数等于零

(1) Hole particle current from E to B (2)Electron particle current from B to E (3)Recombination current in B (4) Hole particle current originating in E and reaching C (5)Reverse electron particle current from c to B (6) Reverse hole particle current from b to c (What is difference between \current\ and\particle current ? OE F Schubert, Rensselaer Polytechnic Institute, 2003

8-2同余式 8.2.1有理整数环中的同余的定义 定义8.5设m是一个正整数,若a,b∈Z,且ba∈(m),亦即m(b-a),则 称b与a模m同余,记作b=a(modm)。不难得到,b与a模m同余就是它们用m做带 余除法所得的余数相同。整数模m同余为一等价关系,验证如下:

引理1: 设P为数域A,B∈Pn,若有P,Q∈P\\, 使-=p(e-B)Q① 则A与B相似. 证:由(ae-B)Q=aQ-PBQ =APL-PBO =RE-A 得PQ=E,PBQ=A 即P=Q,A=QBQ∴A与B相似

1 Equivalence Relations 【Definition】A relation R is defined on a set S if for every pair of elements (a, b), a, b S, a R b is either true or false. If a R b is true, then we say that a is related to b

1.(补充习题)判断以下公式对是否可合一若可合一,则求出最一般的合一 (3)P(f(x),y),P(y,f(b)) 解:令O=,S={p(f(x),y),P(y,f(b))} ①差异集为{f(x),y},做替换{f(x)/y},则 1=0of(x)y}={f(x)/y} S1 =S, ={P((x), f (x), P( f(x),(b)); ②差异集为{x,b},做替换{b/x},则

一、单项选择题(每题1分,共15分。请从题后的备选项中选出你认为正确的选项,将其序号填在题后的括号内。) 1.b2.3.4.B5.a6.b7.b8.d 9.b10.c11.c12.a13.14.c15.c 二、多项选择题(每题2分,共10分。题后的备选项中,至少有两个选项正确。请从题后的备选项中选出你认为正确的所有选项,将其序号填在题中或题后的括号内。错选、漏选均不给分。) 1. ABE 2. ABC 3. ABC 4. ABE 5. AC

一、单项选择题 题分 20 题号 １ ２ ３ ４ ５ ６ ７ ８ ９ １０ 得分 答案 B A A B C D C A D C 题号 １１ １２ １３ １４ １５ １６ １７ １８ １９ ２０ 答案 C A A B B C D A B D

Inertial reference frames In the previous lecture, we derived an expression that related the accelerations observed using two reference frames, A and B, which are in relative motion with respect to each other. aA =aB+(aA/ B)'y'' 22 x (DA/ B) 'y'2'+ TA/B+ X TA/B). (1) Here, aA is the acceleration of particle A observed by one observer, and

1、罗尔中值定理 罗尔(Rolle)定理如果函数f(x)在闭区间 a,b]上连续,在开区间(a,b)内可导,且在区间端 一点的函数值相等,即f(a)=f(b),那末在(a,b) 内至少有一点E(a<