Homework 4: B0-3) hat A32 462人 C(-2) ⊙制 ① 43+) D(3-H) 月 30m
Homework 4:
母1. Axis Column Loads Axis Column Loads Axis Column Loads Axis Column Loads 1-1 1058 1-1 1558 1-1 958 1-1 325 1-2 733 1-2 983 1-2 383 1-3 350 1-3 350 A 2-1 1233 B 2-1 1983 C 2-1 1383 D 2-1 500 2-2 733 2-2 983 2-2 383 2-3 350 2-3 350 3-1 325 3-1 575 3-1 575 3-1 325 2.T=1x10x20x10+1x20x20x5=4000kNm
Homework 5 Check if the thickness of concrete square core tube with 300mm is enough for wind, earthquake and dead loads.Use "Footprint Method”,“Tube Action”and assume the layout as attached (The building is totally supported by the core tube).The height of building is 60m with 20 stories,the concrete strength is 40N/mm2,the wind load is 1kN/m 2, the floor DL is 10kN/m 2,earthquake load is 5%DL
Homework 5 Check if the thickness of concrete square core tube with 300mm is enough for wind, earthquake and dead loads. Use “Footprint Method”, “Tube Action” and assume the layout as attached (The building is totally supported by the core tube). The height of building is 60m with 20 stories, the concrete strength is 40N/mm², the wind load is 1kN/m ², the floor DL is 10kN/m ²,earthquake load is 5% DL
混凝土核心筒 月 5m 30m
30m 5m 5m 30m 混凝土核心筒
Answer: Vertical total load:W=20x30x30x10=180000kN Stress of vertical load-W/A= 180000/(0.3x4x4.7)=31.9MPa Wind induced Mmax=1x30x60x30=54000kNm Earthquake induced Mmax= 5%Wx60x2/3=360000kNm>54000kNm Maximal stress of bending moment= (3/4)x360000/(4.7x4.7x0.3)=+-40.7MPa Maximal stress in pressure is 31.9+40.7-72.6Mpa>40Mpa.The thickness of tube is not enough. 40.7-31.9=8.8 tensile stress,it's not a balance design. How to improve the design?
Answer: Vertical total load: W=20x30x30x10=180000kN Stress of vertical load=W/A= 180000/(0.3x4x4.7)= 31.9MPa Wind induced Mmax=1x30x60x30=54000kNm Earthquake induced Mmax= 5%Wx60x2/3=360000kNm>54000kNm Maximal stress of bending moment= (3/4)x360000/(4.7x4.7x0.3)=+-40.7MPa Maximal stress in pressure is 31.9+40.7=72.6Mpa>40Mpa. The thickness of tube is not enough. 40.7-31.9=8.8 tensile stress, it’s not a balance design. How to improve the design?
Summary of Chapter 3 Tube Action (Square tube,3/4M,0.9V) Frame Action (Total frame action,ib>4ic,P.I.=0.5h Cantilever Action (Pin connection,Apin=4Afix) Shear Lag Effect (Framed tube,o max=1.50)
Summary of Chapter 3 Tube Action (Square tube, 3/4M, 0.9V) Frame Action (Total frame action, ib>4ic, P.I. =0.5h ) Cantilever Action (Pin connection, Δpin=4 Δfix) Shear Lag Effect (Framed tube, σ max=1.5 σ )
Framed tube with Shear Lag Action 无剪力滞 考虑剪力 后应力分 滞后应力 布 分布值 0.5o 1.5o
Framed tube with Shear Lag Action 无剪力滞 后应力分 布 考虑剪力 滞后应力 分布值 0.5 ' 1.5 '
Chapter 4 Total Schematic Analysis of Buildings 4.1.Space Organization of Subsystems 4.2.Total System Analysis 4.3.New Design Concepts 4.4.Examples
Chapter 4 Total Schematic Analysis of Buildings 4.1. Space Organization of Subsystems 4.2. Total System Analysis 4.3. New Design Concepts 4.4. Examples
4.1 Space Organization of Subsystems How to use an overall approach to deal with the subsystem design? Wall,roof,floor components are both space organizing and structural subsystems In early design phase,it is creative to consider the space form with structural thinking
4.1 Space Organization of Subsystems How to use an overall approach to deal with the subsystem design? Wall, roof, floor components are both space organizing and structural subsystems In early design phase, it is creative to consider the space form with structural thinking
Example:Milwaukee War Memorial ☑∥HF1∥1A
Example: Milwaukee War Memorial
