当前位置:高等教育资讯网  >  中国高校课件下载中心  >  大学文库  >  浏览文档

《材料力学》(双语版)第十一章 能量方法

资源类别:文库,文档格式:PPT,文档页数:66,文件大小:1.16MB,团购合买
11-1变形能的普遍表达式 11-2莫尔定理(单位力法 11-3卡氏定理
点击下载完整版文档(PPT)

Mechanics of materials CHAPTERII ENERGYMETHODS

Mechanics of Materials

第十一一方

CHAPTERII ENERGY METHOD D811-1 GENERAL EXPRESSIONS OF THE STRAIN ENERGY S811-2 MOHRS THEOREM(METHOD OF UNIT FORCE □]§11-3 CATIGLIANOS THEOREM

CHAPTER 11 ENERGY METHOD §11–1 GENERAL EXPRESSIONS OF THE STRAIN ENERGY §11–2 MOHR’S THEOREM(METHOD OF UNIT FORCE) §11–3 CATIGLIANO’S THEOREM

第十一章能量方法 □§11-1变形能的普遍表达式 □§11-2莫尔定理(单位力法 §11-3卡氏定理

第十一章 能量方法 §11–1 变形能的普遍表达式 §11–2 莫尔定理(单位力法) §11–3 卡氏定理

ENERGYMETHOD 8 11-1 GENERAL EXPRESSIONS OF THE STRAIN ENERGY 、 Principle of energy Strain energy stored in the elastic body is equal to the work done by external forces, that is: U-W Method to analyze and calculate displacements deformations and internal forces of deformable bodies by this kind of relation is called energy method 2, Calculation of the strain energy of rods 1). Calculation of the strain energy of rods in tension or compression N2(x) dx or U= Density of the 丿2EA =/2E, 4: strain energy. O8

§11–1 GENERAL EXPRESSIONS OF THE STRAIN ENERGY 1、Principle of energy: 2、Calculation of the strain energy of rods: 1). Calculation of the strain energy of rods in tension or compression:  = L x EA N x U d 2 ( ) 2 = = n i i i i i E A N L U 1 2 2  2 1 u = Strain energy stored in the elastic body is equal to the work done by external forces,that is: U=W Method to analyze and calculate displacements 、deformations and internal forces of deformable bodies by this kind of relation is called energy method. or Density of the strain energy:

能量方法 §11-1变形能的普遍表达式 能量原理: 弹性体内部所贮存的变形能,在数值上等于外力所作 的功,即 U=w 利用这种功能关系分析计算可变形固体的位移、变形 和内力的方法称为能量方法。 二、杆件变形能的计算: 1.轴向拉压杆的变形能计算: N2(x) xdx或U=∑ 丿2EA NL比能:=2E 2E

§11–1 变形能的普遍表达式 一、能量原理: 二、杆件变形能的计算: 1.轴向拉压杆的变形能计算:  = L x EA N x U d 2 ( ) 2 = = n i i i i i E A N L U 1 2 2 或  2 1 比能: u = 弹性体内部所贮存的变形能,在数值上等于外力所作 的功,即 U=W 利用这种功能关系分析计算可变形固体的位移、变形 和内力的方法称为能量方法

ENERGYMETHOD 2. Calculation of the strain energy of rods in torsion U= M(x) m4 or U L 2GIp 2G:/ P Density of the strain energyr =ty 2 3. Calculation of strain energy of rods in bending U= M-(x)dx or U=>il b2EⅠ Density of the strain energy: u=O 2

2. Calculation of the strain energy of rods in torsion:  = L P n x GI M x U d 2 ( ) 2 = = n i i Pi ni i G I M L U 1 2 2  2 1 u = 3. Calculation of strain energy of rods in bending:  = L x EI M x U d 2 ( ) 2 = = n i i i i i E I M L U 1 2 2  2 1 u = or Density of the strain energy: or Density of the strain energy:

能量方法 2.扭转杆的变形能计算: U= M(x) dx或U=SMn L 2GIp F-I 2G: Ip 比能:u 2 tr 3.弯曲杆的变形能计算: M(x) M U= dx或U=∑ 丿2E 2E/ 比能:=1og 2

2.扭转杆的变形能计算:  = L P n x GI M x U d 2 ( ) 2 = = n i i Pi ni i G I M L U 1 2 2 或  2 1 比能: u = 3.弯曲杆的变形能计算:  = L x EI M x U d 2 ( ) 2 = = n i i i i i E I M L U 1 2 2 或  2 1 比能: u =

ENERGYMETHOD 3 General expressions of the strain energy Strain energy is independent of the order of loading Deformations due to mutually independent load may be summed up each other 0= N2( dx t M2(x) d x t M2(x) L 2EA .2GⅠ P L 2EI o(x) dx L 2E4 as -> Deflection factor of shear For slender columns, the strain energy due to shearing forces may be neglected M2( U= N2(/~Mx) dx+ 0(×)d L 2EAJL 2GIPJL 2ET

3、General expressions of the strain energy: Strain energy is independent of the order of loading. Deformations due to mutually independent load may be summed up each other. For slender columns,the strain energy due to shearing forces may be neglected. x EI M x x GI M x x EA N x U L L P n L d 2 ( ) d 2 ( ) d 2 ( ) 2 2 2    = + +  + L x EA Q x d 2 ( ) 2 S S → x EI M x x GI M x x EA N x U L L P n L d 2 ( ) d 2 ( ) d 2 ( ) 2 2 2    = + + Deflection factor of shear

能量方法 三、变形能的普遍表达式: 变形能与加载次序无关;相互独立的力(矢)引起的变形能 可以相互叠加。 0= N( d x t (x) d x t M2(x) JL 2EA .2GⅠ L 2EI +Jax)dxa3→剪切烧度因子 细长杆,剪力引起的变形能可忽略不计。 U= N2(/~Mx) dx+ M2( )△ L 2EAJL 2GIPJL 2ET

三、变形能的普遍表达式: 变形能与加载次序无关;相互独立的力(矢)引起的变形能 可以相互叠加。 细长杆,剪力引起的变形能可忽略不计。  + L x EA Q x d 2 ( ) 2 S S → 剪切挠度因子x EI M x x GI M x x EA N x U L L P n L d 2 ( ) d 2 ( ) d 2 ( ) 2 2 2    = + + x EI M x x GI M x x EA N x U L L P n L d 2 ( ) d 2 ( ) d 2 ( ) 2 2 2    = + +

点击下载完整版文档(PPT)VIP每日下载上限内不扣除下载券和下载次数;
按次数下载不扣除下载券;
24小时内重复下载只扣除一次;
顺序:VIP每日次数-->可用次数-->下载券;
共66页,可试读20页,点击继续阅读 ↓↓
相关文档

关于我们|帮助中心|下载说明|相关软件|意见反馈|联系我们

Copyright © 2008-现在 cucdc.com 高等教育资讯网 版权所有