61若煤质分析表中列出如下成分Cu=386%、日=26%S天38 %、Na=0.8%Oa=3,1%M=11.0%A=40.1%而工业分析表 明,实际水分M=16%,试求实际燃料的收到基成分及发热量? 解:1kg空气干燥基燃料折合成实际燃料收到基 1-M 0.16 FO FO 011×386%=364% 1-A1-0.16 ×40.1%=37.8% 1-0.11 1-M 1-0.16 ×26%=2.5% 1-M 1-0.16 ×3.8%=3.6% 1-M 1-0.16 N ×0.8%=0.8% 1-0.11 1-0.16 O 1-M 1-01×3.1%=2.9%
1 6-1 若煤质分析表中列出如下成分FCad＝38.6％、Had＝2.6％、Sad＝3.8 ％、Nad＝0.8％、Oad＝3.1％、Mad＝11.0％、Aad＝40.1％, 而工业分析表 明，实际水分Mar＝16％，试求实际燃料的收到基成分及发热量? 解：1kg空气干燥基燃料折合成实际燃料收到基 1 1 0.16 38.6% 36.4% 1 1 0.11 ar ar ad ad M FC FC M − − = = = − − 1 1 0.16 40.1% 37.8% 1 1 0.11 ar ar ad ad M A A M − − = = = − − 1 1 0.16 3.8% 3.6% 1 1 0.11 ar ar ad ad M S S M − − = = = − − 1 1 0.16 0.8% 0.8% 1 1 0.11 ar ar ad ad M N N M − − = = = − − 1 1 0.16 3.1% 2.9% 1 1 0.11 ar ar ad ad M O O M − − = = = − − 1 1 0.16 2.6% 2.5% 1 1 0.11 ar ar ad ad M H H M − − = = = − −
1-(FCar +Aar +Ha+Sar+Nar +Oar) =1-(0364+0.378+0.025+0.036+0008+0029)=16.0% 收到基(ar) 空干基(ad) 干燥基(d 干燥无灰基(f) C N SbM M 灰分 水分 挥发那分 焦灰
2 ( ) ( ) 1 1 0.364 0.378 0.025 0.036 0.008 0.029 16.0% M FC A H S N O ar ar ar ar ar ar ar = − + + + + + = − + + + + + =
(2)计算煤的发热量 a)无烟煤: Qm,=K0-360010-385004-1000 35797 2.6%=53% daf_aod 0.11-0.401 0.11-0401 (26%+38%+08%+31%)=211% Ka=35588 d=d-0.xA=Va-0.1×Ax 1-M 21.1%-0.1×401%X1 166% -11.0% Qna=K0-360-38500A-1000 =355853600106038500×378%-1000×090=16045(k/kg) Qnya=K0-36000Ma-38500Aa-10000 35797-3600109-38500×378%-10003%=16254(/kg)
3 (2)计算煤的发热量 , , 0 36000 38500 10000 Q K M A V net v ad ad ad ad = − − − a)无烟煤： 1 1 2.6% 5.3% 1 1 0.11 0.401 daf ad ad ad H H M A = = = − − − − ( ) 1 1 2.6% 3.8% 0.8% 3.1% 21.1% 1 1 0.11 0.401 daf ad ad ad V V M A = = + + + = − − − − 1 0.1 0.1 1 1 21.1% 0.1 40.1% 16.6% 1 11.0% daf daf d daf ad ad V V A V A M = − = − − = − = − ① 0 K = 35588 0 K = 35797 ( ) , , 0 36000 38500 10000 35588 36000 11.0% 38500 37.8% 10000 10.3% 16045 / Q K M A V net v ad ad ad ad kJ kg = − − − = − − − = ( ) , , 0 36000 38500 10000 35797 36000 11.0% 38500 37.8% 10000 10.3% 16254 / Q K M A V net v ad ad ad ad kJ kg = − − − = − − − =
b)烟煤: Cnet, vad 100K1-(100K1+2510Ma+Aa)-1260a-16750Ma d21.1%3% 焦炭特性取4级,查表K1=348 Qna=100×348-(100×348+2510(1109%+40.190)-1260×10.3%-16750×11090 =13762(k/g) 4
4 b) 烟煤： Qnet v a d K K M a d Aa d 1260Va d 16750M a d 100 (100 2510)( ) , , = 1 − 1 + + − − Vdaf = 21.1% 35% Mad = 11.0% 3% 焦炭特性取4级，查表 1 K = 348 ( ) , , 100 348 (100 348 2510)(11.0% 40.1%) 1260 10.3% 16750 11.0% 13762 / Qnet v ad kJ kg = − + + − − = 且
6-4已知某窑炉用煤的收到基组成为: 组分 Car ar sar Mar Aar 质量(%) 75.0 6.8 5.0 12 3.5 8.0 a=12,计算:①实际空气量(Nm3kg);②实际烟气量(Nmy kg);③烟气组成。 解:基准:1kg煤。 (1)空气量计算 理论空气量V0: 100(CH 21 124 3232八×224100 0.750.0680.0050.05 100 ×22.4x 12 4 3232 21 83(Nm7/g) 实际空气量V: Va=c0=12×833=10(Wm/kg)
5 6-4 已知某窑炉用煤的收到基组成为： α=1.2，计算：①实际空气量（Nm3 /kg）；②实际烟气量（Nm3 / kg）；③烟气组成。 组分 Car Har Oar Nar Sar Mar Aar 质量（%） 75.0 6.8 5.0 1.2 0.5 3.5 8.0 解：基准：1kg煤。 (1)空气量计算 理论空气量Va 0： ( ) 2 0 0 3 100 100 22.4 21 12 4 32 32 21 0.75 0.068 0.005 0.05 100 22.4 12 4 32 32 21 8.33 ar ar ar ar a o C H S O V V Nm kg = = + + − = + + − = 实际空气量Va： ( ) 0 3 1.2 8.33 10.00 V V Nm kg a a = = =
(2)烟气量计算 理论烟气量V + HO +0+ HM S N 79 ×224+V× 12 0.750.0680.0350.0050.01 79 ×22.4+8.33× 12 32 28 100 =8:80(Nm/kg 实际烟气量V: =+(-)y=880+(12-1)×833=1047(Mm3/kg) 3)烟气组成百分数计算 C≈C/12×224 075/12×224 100% ×100%=13.37% 1047 HD=(H/2+M0/18)×224 ×100%≈(0068/2+0035/18)×224 100%=7.69% 1047
6 (2)烟气量计算 理论烟气量V0： ( ) 2 2 2 2 0 0 0 0 0 0 3 79 22.4 12 2 18 32 28 100 0.75 0.068 0.035 0.005 0.012 79 22.4 8.33 12 2 18 32 28 100 8.80 CO H O SO N ar ar ar ar ar a V V V V V C H M S N V Nm kg = + + + = + + + + + = + + + + + = 实际烟气量V： ( ) ( ) ( ) 0 0 3 1 8.80 1.2 1 8.33 10.47 V V V Nm kg = + − = + − = a (3)烟气组成百分数计算 2 12 22.4 0.75 12 22.4 100% 100% 13.37% 10.47 Car CO V = = = ( ) ( ) 2 2 18 22.4 0.068 2 0.035 18 22.4 100% 100% 7.69% 10.47 H M ar ar H O V + + = = =
Sa/32×224 0005/32×22.4 ×100%= 100%=0.03% 1047 O=(a-)l0×21% 12-1)×8.33×21% 100%= 100%=3.34% Na/28×224+V×79% 100% 0012/28×224+10.00×79% 100 10.47 =75.55% 烟气中CO2、H2O、SO2、O2、N2的百分含量分别为 13.37%、7.69%、0.03%、3.34%、75.55%
7 2 32 22.4 0.005 32 22.4 100% 100% 0.03% 10.47 ar S SO V = = = ( ) ( ) 0 2 1 21% 1.2 1 8.33 21% 100% 100% 3.34% 10.47 Va O V − − = = = 2 28 22.4 79% 100% 0.012 28 22.4 10.00 79% 100% 10.47 75.55% N V ar a N V + = + = = 烟气中CO2、H2O、SO2、O2、N2的百分含量分别为： 13.37% 、7.69% 、0.03% 、3.34% 、75.55%
6-6某窑炉使用发生炉煤气为燃料,其组成为(%): 组分 cO CO CH4 C2H H2S H2O 含量(%)5.5260125250.50.24701.34.5 燃烧时α=12,计算:①燃烧所需实际空气用量(Nm3/Nm3煤气) ②实际湿烟气生成量(Nm3/Nm3煤气) ③千烟气及湿烟气组成百分率 解:(1)计算INm3煤气燃烧所需要的空气量 理论空气量: CO+H2+2CH4+m+,+rH2s-O 100 [0×026+05×0125+2×005+25×005+15×003-002×100 1298Nm3/Nm3煤气 实际空气量==12×1298=156Wm/Mm煤气) (2)计算Nm3煤气燃烧生成的烟气量
8 6-6 某窑炉使用发生炉煤气为燃料，其组成为（%）： 燃烧时α=1.2，计算：①燃烧所需实际空气用量（ Nm3 / Nm3煤 气）； ②实际湿烟气生成量（Nm3 / Nm3煤气）； ③干烟气及湿烟气组成百分率。 组分 CO2 CO H2 CH 4 C2H 2 O2 N 2 H 2S H 2O 含量（%） 5.5 26.0 12.5 2.5 0.5 0.2 47.0 1.3 4.5 解：（1）计算1Nm3煤气燃烧所需要的空气量 理论空气量： 0 2 4 2 2 3 3 1 1 3 100 2 2 2 4 2 21 100 0.5 0.26 0.5 0.125 2 0.025 2.5 0.005 1.5 0.013 0.002 21 1.298Nm / Nm a m n n V CO H CH m C H H S O = + + + + + − = + + + + − = 煤气 实际空气量： ( ) 0 3 3 1.2 1.298 1.558 V V Nm Nm a a = = = 煤气 （2）计算1Nm3煤气燃烧生成的烟气量
CO2+CO+H20+3CH+m+C H,+2H2 S+N2+H2+v 79 100 =(0.055+0.26+0.045+3×0.025+3×0.005+2×0.013+0.47+0.125)+1.298 2.0(Mm72/Nm煤气) 实际烟气量: =0+(a-1)7=21+(1.2-1)×1298=236(Mm/Mm煤气 (3)干烟气及湿烟气组成百分率 湿烟气组成百分率 CO2=(CO2+CO+CH4+mCmH,)/V =(0.055+0.26+0.025+2×0.005)/236 =14.83% Wuo=ho+h+2Ch,+-CA+hs 20 0.045+0.125+2×0.025+0.005+0.013 0238(Nm3/Mm3煤 气) H2O=Vmo/V=0.238/2.36=10.08%
9 ( ) ( ) 0 0 2 2 4 2 2 2 3 3 79 3 2 2 100 79 0.055 0.26 0.045 3 0.025 3 0.005 2 0.013 0.47 0.125 1.298 100 2.10 / m n a n V CO CO H O CH m C H H S N H V Nm Nm = + + + + + + + + + = + + + + + + + + = 煤气 实际烟气量： ( ) ( ) ( ) 0 0 3 3 1 2.1 1.2 1 1.298 2.36 V V V Nm Nm = + − = + − = a 煤气 （3）干烟气及湿烟气组成百分率 ( ) ( ) 2 2 4 / 0.055 0.26 0.025 2 0.005 / 2.36 14.83% CO CO CO CH mC H V = + + + m n = + + + = ( ) 2 2 2 4 2 3 3 2 2 0.045 0.125 2 0.025 0.005 0.013 0.238 / H O m n n V H O H CH C H H S Nm Nm = + + + + = + + + + = 煤气 2 2 H O V V = = = H O / 0.238/ 2.36 10.08% 湿烟气组成百分率
H2S/=0.013/2.36=0.55% N2=(N2+QJ0×79/100)/V =(0.47+12×1.298×79/100)/236=7203% (a-1)Va×21/10002×1.298×21/100 2.31% 2.36 干烟气组成百分率 10=236-0238=2122Nm0Mm煤气) CO2=(CO2+CO+CH4 +mC Hn)/vd 0.055+0.26+0025+2×0.005)/2.122=1649% SO2=H2S/V=0.013/2.122=0.61% N2=(N2+a10×7100 0.47+1.2×1.298×79/100)/2.122=80.11% (a-1)V0×21/1000.2×1.298×21/100 =2.57% 2.122 10
10 2 2 SO H S V = = = / 0.013/ 2.36 0.55% ( ) ( ) 0 2 2 79/100 / 0.47 1.2 1.298 79/100 / 2.36 72.03% N N V V = + a = + = 干烟气组成百分率 ( ) 2 3 3 2.36 0.238 2.122 / V V V Nm Nm d H O = − = − = 煤气 ( ) 0 2 1 21/100 0.2 1.298 21/100 2.31% 2.36 Va O V − = = = ( ) ( ) 2 2 4 / 0.055 0.26 0.025 2 0.005 / 2.122 16.49% d CO CO CO CH mC H V = + + + m n d = + + + = 2 2 / 0.013/ 2.122 0.61% d d SO H S V = = = ( ) ( ) 0 2 2 79/100 / 0.47 1.2 1.298 79/100 / 2.122 80.11% d N N V V = + a d = + = ( ) 0 2 1 21/100 0.2 1.298 21/100 2.57% 2.122 d a d V O V − = = =